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4x^2+74x-164=0
a = 4; b = 74; c = -164;
Δ = b2-4ac
Δ = 742-4·4·(-164)
Δ = 8100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8100}=90$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(74)-90}{2*4}=\frac{-164}{8} =-20+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(74)+90}{2*4}=\frac{16}{8} =2 $
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